For spontaneous polymerization, which of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A, B, D) For a process to be spontaneous, the Gibbs free energy change, $\Delta G$, must be negative. Polymerization involves the association of mono

Vedclass · Accepted Answer

$\Delta S$ is negative

Vedclass · Answer

(A, B, D) For a process to be spontaneous, the Gibbs free energy change, $\Delta G$, must be negative. Polymerization involves the association of monomer units into a long chain, which leads to a decrease in the randomness of the system, meaning $\Delta S$ is negative. According to the Gibbs-Helmholtz equation, $\Delta G = \Delta H - T\Delta S$. Since $\Delta G < 0$ and $\Delta S < 0$, for the process to be spontaneous, $\Delta H$ must be negative and its magnitude must be greater than $T\Delta S$.

For spontaneous polymerization, which of the following is (are) correct?

Similar Questions

The catalyst used for the polymerisation of olefins is

Which amongst the following molecules on polymerization produces neoprene?

The expected reactivity of the monomers shown below towards cationic polymerization follows the order:
$I: CH_2=CH-CO_2CH_3$
$II: CH_2=CH-Cl$
$III: CH_2=CH-CH_3$
$IV: CH_2=CH-Ph$

The correct statement regarding $X$ and $Y$ in the following set of reactions is:
$nCH_2=CH_2 \xrightarrow[(C_2H_5)_3Al, TiCl_4]{333-343 \ K, 6-7 \ atm} Y$
$nCH_2=CH_2 \xrightarrow[(C_6H_5COO)_2]{350-570 \ K, 1000-2000 \ atm} X$

Which among the following polymers does $NOT$ need a peroxide initiator for synthesis?

Vedclass Test Series

Exam Paper Generator

Online Exam Module