For a strong electrolyte,the molar conductivity is given by $\wedge _m = \wedge _m^o - 10 \sqrt{C}$. Calculate $\wedge _m$ at $0.01 \ M$ if its value at $0.16 \ M$ is $200 \ S \ cm^2 \ mol^{-1}$.

$0.01\, S\, m^2\, mol^{-1} = $ ....... $S\, cm^2\, mol^{-1}$

The correct order of equivalent conductances at infinite dilution in water at room temperature for $H^{+}$, $K^{+}$, $CH_{3}COO^{-}$ and $HO^{-}$ ions is

At $291 \ K$,a saturated solution of $BaSO_4$ was found to have a specific conductivity of $3.648 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$ and that of the water used is $1.25 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$. If the ionic conductances of $Ba^{2+}$ and $SO_4^{2-}$ are $110$ and $136.6 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively,the solubility of $BaSO_4$ at $291 \ K$ will be (Atomic masses: $Ba=137, S=32, O=16$)

$A$ conductivity cell with two electrodes (shaded sides) is half-filled with an infinitely dilute aqueous solution of a weak electrolyte. If the volume is doubled by adding more water at a constant temperature,the molar conductivity of the cell will -

Two solutions of electrolytes $X$ and $Y$ are taken in two beakers and diluted by adding $500 \ mL$ of water. The molar conductivity $(\Lambda_m)$ of $X$ increases by $1.5$ times,while that of $Y$ increases by $20$ times. What could be the electrolytes $X$ and $Y$?