For the adsorption of a solution on a solid s | vedclass

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(D) The Freundlich adsorption isotherm equation is $\frac{x}{m} = k C^{1/n}$.Taking the logarithm on both sides,we get: $\log (\frac{x}{m}) = \log k +

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$\frac{1}{n} = 0$

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(D) The Freundlich adsorption isotherm equation is $\frac{x}{m} = k C^{1/n}$.Taking the logarithm on both sides,we get: $\log (\frac{x}{m}) = \log k + \frac{1}{n} \log C$.This is a linear equation of the form $y = mx + c$,where $y = \log (\frac{x}{m})$,$x = \log C$,slope $m = \frac{1}{n}$,and intercept $c = \log k$.The given graph is a horizontal line parallel to the $\log C$ axis,which means the slope of the line is zero.Therefore,$\frac{1}{n} = 0$.

For the adsorption of a solution on a solid surface,the Freundlich adsorption isotherm is given by $\frac{x}{m} = k C^{1/n}$. The plot of $\log (\frac{x}{m})$ versus $\log C$ is shown below. This corresponds to which of the following conditions?

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