For the below given cyclic hemiacetal (X),the | vedclass

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(A) To convert the cyclic hemiacetal structure into a Haworth projection (pyranose form),we follow these steps:$1$. Identify the carbon atoms in the c

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(A) To convert the cyclic hemiacetal structure into a Haworth projection (pyranose form),we follow these steps:$1$. Identify the carbon atoms in the chain. The hemiacetal is formed between the $C_1$ (anomeric carbon) and the $C_5$ hydroxyl group.$2$. In the Haworth projection,the oxygen atom is placed at the top right corner of the ring.$3$. Groups on the right side of the Fischer projection are placed pointing downwards,and groups on the left side are placed pointing upwards.$4$. For the given structure,the $C_2-OH$ is on the left (up),$C_3-OH$ is on the right (down),$C_4-OH$ is on the left (up),and $C_5-CH_2OH$ is pointing upwards.$5$. Comparing this configuration to the given options,the structure in option $(A)$ correctly represents the spatial arrangement of the hydroxyl groups and the hydroxymethyl group.

For the below given cyclic hemiacetal $(X)$,the correct pyranose structure is.

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