For the circuit shown below,the Boolean polyn | vedclass

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(D) In the given circuit,there are two parallel branches. Each branch consists of two switches connected in series. The upper branch has switches $\si

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$(\sim p \wedge q) \vee (p \wedge \sim q)$

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(D) In the given circuit,there are two parallel branches. Each branch consists of two switches connected in series. The upper branch has switches $\sim p$ and $q$ in series,which corresponds to the expression $(\sim p \wedge q)$. The lower branch has switches $p$ and $\sim q$ in series,which corresponds to the expression $(p \wedge \sim q)$. Since the two branches are connected in parallel,the total Boolean polynomial is the disjunction of the two expressions: $(\sim p \wedge q) \vee (p \wedge \sim q)$.

For the circuit shown below,the Boolean polynomial is:

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