For the circuit shown in the figure,the curre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the potential at junction $A$ be $V_A = 3 	ext{ V}$ and at junction $C$ be $V_C = 0 	ext{ V}$.Let the potential at junction $B$ be $V_B$.App

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(A) Let the potential at junction $A$ be $V_A = 3 	ext{ V}$ and at junction $C$ be $V_C = 0 	ext{ V}$.Let the potential at junction $B$ be $V_B$.Applying Kirchhoff's Current Law $(KCL)$ at junction $B$:$\frac{V_B - V_A}{6} + \frac{V_B - V_C}{12} + \frac{V_B - V_C}{12} = 0$$\frac{V_B - 3}{6} + \frac{V_B}{12} + \frac{V_B}{12} = 0$Multiplying by $12$:$2(V_B - 3) + V_B + V_B = 0$$2V_B - 6 + 2V_B = 0$$4V_B = 6 \implies V_B = 1.5 	ext{ V}$.The current through the $6 \Omega$ resistor between $A$ and $B$ is $I = \frac{V_A - V_B}{6} = \frac{3 - 1.5}{6} = \frac{1.5}{6} = 0.25 	ext{ A}$.

For the circuit shown in the figure,the current through the $6 \Omega$ resistor connected between the junctions $A$ and $B$ is (in $A$)

Similar Questions

The electric current $i$ in the circuit shown is (in $\text{ A}$)

The Wheatstone bridge is in a balanced condition in the given figure, then $X = (in $Omega$)?$

The total length of the potentiometer wire $AB$ is $50 \text{ cm}$ in the arrangement as shown in the figure. If $P$ is the point where the galvanometer shows zero reading, then the length $AP$ is . . . . . . $\text{ cm}$.

In the given circuit diagram,a wire is joining points $B$ and $D$. The current in this wire is ............. $A$.

The potential difference $(V_{A}-V_{B})$ between the points $A$ and $B$ in the given part of the circuit is

Vedclass Test Series

Exam Paper Generator

Online Exam Module