For the coagulation of a negatively charged c | vedclass

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(A) According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the active ion (the ion carrying a charge op

Vedclass · Accepted Answer

$AlCl_3$

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(A) According to the Hardy-Schulze rule,the coagulating power of an electrolyte depends on the valency of the active ion (the ion carrying a charge opposite to that of the colloidal particles). For a negatively charged sol,the coagulating power of the cation increases with its valency. The valencies of the cations in the given options are: $Al^{3+}$ $(AlCl_3)$,$K^+$ $(K_2SO_4)$,$Na^+$ $(NaOH)$,and $H^+$ $(HCl)$. Since $Al^{3+}$ has the highest valency $(+3)$,it has the highest coagulating power. Therefore,the minimum amount of $AlCl_3$ is required for coagulation.

For the coagulation of a negatively charged clay sol in water,the minimum amount of which of the following is required?

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