For the energy levels in an atom,which one of | vedclass

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(D) $1$. According to the $(n+l)$ rule,the energy of an orbital increases with the value of $(n+l)$. For $4s$,$(n+l) = 4+0 = 4$. For $3d$,$(n+l) = 3+2

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Both $(b)$ and $(c)$ are correct.

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(D) $1$. According to the $(n+l)$ rule,the energy of an orbital increases with the value of $(n+l)$. For $4s$,$(n+l) = 4+0 = 4$. For $3d$,$(n+l) = 3+2 = 5$. Thus,$3d$ has higher energy than $4s$. Statement $(a)$ is incorrect.$2$. The maximum number of electrons in a principal energy level $n$ is given by $2n^2$. For $n=5$,maximum electrons $= 2(5)^2 = 2(25) = 50$. Statement $(b)$ is correct.$3$. For the second principal energy level $(n=2)$,the orbitals present are $2s$ ($1$ orbital) and $2p$ ($3$ orbitals),totaling $4$ orbitals. The maximum number of electrons is $2(2)^2 = 8$. Statement $(c)$ is correct.$4$. Since both $(b)$ and $(c)$ are correct,the correct option is $(d)$.

$X = x$	$0$	$1$	$2$	$3$
$P(X = x)$	$\frac{1}{10}$	$\frac{2}{10}$	$\frac{3}{10}$	$\frac{4}{10}$

For the energy levels in an atom,which one of the following statements is correct?

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