For the finite A.P. 85, 80, 75, ldots, -30, f | vedclass

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(C) The given $A.P.$ is $85, 80, 75, \ldots, -30$.Here,the first term $a = 85$ and the common difference $d = 80 - 85 = -5$.The last term $l = -30$.To

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$-10$

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(C) The given $A.P.$ is $85, 80, 75, \ldots, -30$.Here,the first term $a = 85$ and the common difference $d = 80 - 85 = -5$.The last term $l = -30$.To find the $n^{th}$ term from the end of an $A.P.$,the formula is $l - (n - 1)d$.Here,we need the $5^{th}$ term from the end,so $n = 5$.$5^{th} 	ext{ term from the end} = l - (5 - 1)d$$= -30 - (4)(-5)$$= -30 + 20$$= -10$.

For the finite $A.P.$ $85, 80, 75, \ldots, -30,$ find the $5^{th}$ term from the end.

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