(C) For a $1^{st}$ order reaction,the half-life $(t_{1/2})$ is given by the formula $t_{1/2} = \frac{0.693}{k}$.Since the half-life is independent of

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(C) For a $1^{st}$ order reaction,the half-life $(t_{1/2})$ is given by the formula $t_{1/2} = \frac{0.693}{k}$.Since the half-life is independent of the initial concentration $[A]$,changing the concentration will not affect the half-life.Therefore,the half-life remains $5 \ minutes$.

Class 12 Chemistry Chemical Kinetics First Order reaction

Easy

For the $1^{st}$ order reaction,the half-life is $5 \ minutes$ when $[A] = 0.1 \ M$. If the concentration of $[A]$ becomes twice,then the half-life becomes:

A
half
B
double
C
remains same
D
$10 \ minutes$

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Chemical Kinetics

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First Order reaction

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For the $1^{st}$ order reaction,the half-life is $5 \ minutes$ when $[A] = 0.1 \ M$. If the concentration of $[A]$ becomes twice,then the half-life becomes:

Similar Questions

The time required for $60 \%$ completion of a first order reaction is $50 \ min$. The time required for $93.6 \%$ completion of the same reaction will be (in $min$)

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