For the following $APs$,write the first term and the common difference: $\frac{1}{3}, \frac{5}{3}, \frac{9}{3}, \frac{13}{3}, \ldots$

(N/A) The given arithmetic progression is $\frac{1}{3}, \frac{5}{3}, \frac{9}{3}, \frac{13}{3}, \ldots$
The first term $(a)$ is the first number in the sequence,so $a = \frac{1}{3}$.
The common difference $(d)$ is calculated by subtracting the first term from the second term:
$d = \frac{5}{3} - \frac{1}{3} = \frac{4}{3}$.
Thus,the first term is $\frac{1}{3}$ and the common difference is $\frac{4}{3}$.