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(B) Friedel-Crafts alkylation of benzene with $n$-propyl chloride gives $iso$-propylbenzene as the major product because the $n$-propyl carbocation un

Vedclass · Accepted Answer

$B$ and $C$ only

Vedclass · Answer

(B) Friedel-Crafts alkylation of benzene with $n$-propyl chloride gives $iso$-propylbenzene as the major product because the $n$-propyl carbocation undergoes rearrangement to form a more stable $iso$-propyl carbocation: $CH_3CH_2CH_2^+ \rightarrow CH_3CH^+CH_3$.
Thus, Statement $B$ is correct.
Furthermore, alkylation of benzene increases the electron density on the ring, making it more reactive towards further electrophilic substitution, hence multiple substitution is a common byproduct. Thus, Statement $C$ is also correct.

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