For the formation of NH_{3(g)} from its const | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The formation of $NH_3$ follows Le Chatelier's principle for the reaction: $N_{2(g)} + 3H_{2(g)} ightleftharpoons 2NH_{3(g)} + 	ext{Heat}$.Numb

Vedclass · Accepted Answer

high pressure and low temperature

Vedclass · Answer

(A) The formation of $NH_3$ follows Le Chatelier's principle for the reaction: $N_{2(g)} + 3H_{2(g)} ightleftharpoons 2NH_{3(g)} + 	ext{Heat}$.Number of moles of reactants $= 1 + 3 = 4$.Number of moles of products $= 2$.Since the number of moles of products is less than the number of moles of reactants,an increase in pressure will shift the equilibrium in the forward direction.As the reaction is exothermic (heat is released),a decrease in temperature will shift the equilibrium in the forward direction.Therefore,high pressure and low temperature are the favourable conditions for the formation of $NH_3$.

For the formation of $NH_{3(g)}$ from its constituent elements,the favourable conditions for its formation are

Similar Questions

In the equilibrium $N_2 + 3H_2 \rightleftharpoons 2NH_3 + 22 \ kcal$,the formation of ammonia is favoured by

What happens when a saturated solution of $CO_2$ is heated?

When $KOH$ is dissolved in water,heat is evolved. If the temperature is raised,the solubility of $KOH$

The yellow solution of $Na_2CrO_4$ changes to orange red on passing $CO_2$ gas due to the formation of:

In the $N_2 + 3H_2 \rightleftharpoons 2NH_3$ reversible reaction,an increase in pressure will favour:

Vedclass Test Series

Exam Paper Generator

Online Exam Module