For the gaseous reactions (I) and (II),the eq | vedclass

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(D) Given reactions:$I. \frac{1}{2} N_{2(g)} + O_{2(g)} \rightleftharpoons NO_{2(g)}$ with equilibrium constant $X$.$II. 2 NO_{2(g)} \rightleftharpoon

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$Z = \frac{1}{X^2Y}$

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(D) Given reactions:$I. \frac{1}{2} N_{2(g)} + O_{2(g)} ightleftharpoons NO_{2(g)}$ with equilibrium constant $X$.$II. 2 NO_{2(g)} ightleftharpoons N_2O_{4(g)}$ with equilibrium constant $Y$.Target reaction $(III): N_2O_{4(g)} ightleftharpoons N_{2(g)} + 2 O_{2(g)}$.To obtain reaction $(III)$,we reverse reaction $(II)$ and add it to twice the reverse of reaction $(I)$ (or simply reverse the sum of $2 	imes Eq(I) + Eq(II)$):$2 	imes Eq(I): N_{2(g)} + 2 O_{2(g)} ightleftharpoons 2 NO_{2(g)}$ with constant $X^2$.$Eq(II): 2 NO_{2(g)} ightleftharpoons N_2O_{4(g)}$ with constant $Y$.Adding these gives: $N_{2(g)} + 2 O_{2(g)} ightleftharpoons N_2O_{4(g)}$ with constant $K = X^2Y$.Since reaction $(III)$ is the reverse of this sum,its equilibrium constant $Z = \frac{1}{K} = \frac{1}{X^2Y}$.

Similar Questions

If the equilibrium constant for the reaction,$2 SO_2 + O_2 \rightleftharpoons 2 SO_3$ is $64$ at $500 \ K$,then the equilibrium constant for the reaction $SO_3 \rightleftharpoons SO_2 + \frac{1}{2} O_2$ at the same temperature is

For the reversible reaction:
$A_{(s)} + B_{(g)} \rightleftharpoons C_{(g)} + D_{(g)}$;
$\Delta G^{\circ} = -350 \ kJ$
Which one of the following statements is true?

The equilibrium constant for the given reaction is $100$.
$N_{2(g)} + 2 O_{2(g)} \rightleftharpoons 2 NO_{2(g)}$
What is the equilibrium constant for the reaction given below?
$NO_{2(g)} \rightleftharpoons \frac{1}{2} N_{2(g)} + O_{2(g)}$

At $780 \ K$ and $10 \ atm$ pressure,the equilibrium constant for the reaction $2 \ A_{(g)} \rightleftharpoons B_{(g)} + C_{(g)}$ is $3.52$. At the same temperature and $7.04 \ atm$ pressure,the equilibrium constant for the same reaction is:

For the system $A_{(g)} + 2B_{(g)} \rightleftharpoons C_{(g)}$,the equilibrium concentrations are $[A] = 0.06 \ mol/L$,$[B] = 0.12 \ mol/L$,and $[C] = 0.216 \ mol/L$. The $K_{eq}$ for the reaction is:

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