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Question

(A) The acidic strength of phenols is increased by electron-withdrawing groups $(-NO_2)$ and decreased by electron-donating groups $(-OCH_3)$.$pK_{a}$

Vedclass · Accepted Answer

$(E) < (C) < (A) < (D) < (B)$

Vedclass · Answer

(A) The acidic strength of phenols is increased by electron-withdrawing groups $(-NO_2)$ and decreased by electron-donating groups $(-OCH_3)$.$pK_{a}$ is inversely proportional to acidic strength.$(A)$ Phenol$(B)$ $p$-Nitrophenol (Strongest acid due to $-M$ and $-I$ effect of $-NO_2$)$(C)$ $m$-Methoxyphenol ($-I$ effect of $-OCH_3$ increases acidity compared to phenol)$(D)$ $o$-Nitrophenol (Strong acid due to $-I$ and $-M$ effect,but slightly weaker than $p$-nitrophenol due to intramolecular $H$-bonding)$(E)$ $p$-Methoxyphenol (Strongest electron-donating effect $+M$ of $-OCH_3$ decreases acidity the most)Acidic strength order: $(B) > (D) > (A) > (C) > (E)$Therefore,the increasing order of $pK_{a}$ is: $(E) < (C) < (A) < (D) < (B)$.

For the given compounds,the correct order of increasing $pK_{a}$ value is:

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