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(B) The work done in a cyclic process on a $P-V$ diagram is equal to the area enclosed by the loop.For the triangle $CAB$:The base of the triangle alo

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$10$

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(B) The work done in a cyclic process on a $P-V$ diagram is equal to the area enclosed by the loop.For the triangle $CAB$:The base of the triangle along the $V$-axis is $\Delta V = 5 - 1 = 4 \, m^3$.The height of the triangle along the $P$-axis is $\Delta P = 6 - 1 = 5 \, Pa$.The area of the triangle is given by $	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$.$	ext{Area} = \frac{1}{2} 	imes 4 	imes 5 = 10 \, J$.Since the cycle $CAB$ is traversed in the counter-clockwise direction,the work done is negative. However,in magnitude,the work done is $10 \, J$.

For the given cyclic process $CAB$ as shown for a gas,the work done is ..... $J$.

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