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(C) The molecule $x$ is $N$-phenylbenzamide. It contains two phenyl rings attached to an amide group $(-CONH-)$.In the ring attached to the nitrogen a

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$p$ and $s$

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(C) The molecule $x$ is $N$-phenylbenzamide. It contains two phenyl rings attached to an amide group $(-CONH-)$.In the ring attached to the nitrogen atom, the lone pair on the nitrogen atom is in conjugation with the benzene ring, making it an activating group. This group is ortho/para directing.In the ring attached to the carbonyl carbon, the carbonyl group $(-C=O)$ is a deactivating group and is meta-directing.Therefore, the electrophilic aromatic substitution will occur on the ring attached to the nitrogen atom. The ortho and para positions relative to the nitrogen atom are the most electron-rich sites.In the given structure, $u$ represents the para position and $s$ represents the ortho position relative to the nitrogen atom. Thus, the electrophile will preferentially attack at these positions.

Column-$I$	Column-$II$
$(i)$ Substitution reaction	$(p)$ $CH_2=CH_2 + Br_2 \to CH_2Br-CH_2Br$
$(ii)$ Addition reaction	$(q)$ $C_6H_6 + NO_2^+ \to C_6H_5NO_2 + H^+$
$(iii)$ Electrophilic addition reaction	$(r)$ $CH_3Cl + NaOH \to CH_3OH + NaCl$
$(iv)$ Electrophilic substitution reaction	$(s)$ $CH_3CH_2OH \xrightarrow[\Delta]{Al_2O_3} CH_2=CH_2$
$(v)$ Elimination reaction

For the given molecule, $x$, the preferred site for the attack of the electrophile is:

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