For the given reaction:(Cyclohexyl)-CH=CH-(Cy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of an alkene with hot acidic $KMnO_4$ (oxidative cleavage) results in the cleavage of the $C=C$ double bond.For the given reactant,$1

Vedclass · Accepted Answer

Cyclohexanecarboxylic acid

Vedclass · Answer

(A) The reaction of an alkene with hot acidic $KMnO_4$ (oxidative cleavage) results in the cleavage of the $C=C$ double bond.For the given reactant,$1,2$-dicyclohexylethane,the oxidative cleavage of the double bond yields two molecules of cyclohexanecarboxylic acid as the major product.The reaction is:$(C_6H_{11})CH=CH(C_6H_{11}) \xrightarrow{KMnO_4/H^+} 2 C_6H_{11}COOH$Thus,the major product '$P$' is cyclohexanecarboxylic acid.

For the given reaction:
(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)
'$P$' is:

Similar Questions

The major product of the following reaction is $:$

When an alcoholic solution of ethylene dibromide $(Br-CH_2-CH_2-Br)$ is heated with granulated zinc,the compound formed is:

The number of alkenyl groups possible from $C_{4}H_{7}$ are

The formation of isopropyl chloride from the reaction between propene and $HCl$ is based on which of the following?

Appropriate reducing agent for the following conversion is:
$CH_2=CH-CH_2-CHO \to CH_3-CH_2-CH_2-CH_2OH$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

For the given reaction:(Cyclohexyl)-$CH$=$CH$-(Cyclohexyl) $\xrightarrow{KMnO_4/H^+}$ '$P$' (major product)'$P$' is: