For the identification of beta-naphthol using | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In the dye test,the phenolic $-OH$ group is converted to the phenoxide ion $-O^{\ominus}$ in the presence of a base.This phenoxide ion is a strong

Vedclass · Accepted Answer

alkaline solution of $\beta$-naphthol.

Vedclass · Answer

(D) In the dye test,the phenolic $-OH$ group is converted to the phenoxide ion $-O^{\ominus}$ in the presence of a base.This phenoxide ion is a strong activating group that increases the electron density on the aromatic ring,thereby facilitating Electrophilic Aromatic Substitution $(EAS)$ with the diazonium salt.This activation is only possible in an alkaline solution.Therefore,the correct option is $(D)$.

For the identification of $\beta$-naphthol using dye test,it is necessary to use :

Similar Questions

The compound that would produce a nauseating smell/odour with a hot mixture of chloroform and ethanolic potassium hydroxide is

The amine or salt of amine which gives a positive test with a mixture of chloroform and alcoholic $KOH$ solution is:

Primary,secondary and tertiary amines can be separated using :-

Which of the following does not reduce Tollen’s reagent?

Which of the following properties is $NOT$ applicable to $CH_3CN$ (Ethanenitrile)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module