For the reaction,XA + YB rightarrow ZC,if fra | vedclass

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Question

(A) For a general reaction $XA + YB \rightarrow ZC$,the rate of reaction is given by:Rate $= -\frac{1}{X} \frac{d[A]}{dt} = -\frac{1}{Y} \frac{d[B]}{d

Vedclass · Accepted Answer

The value of $X = Y = Z = 3$

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(A) For a general reaction $XA + YB ightarrow ZC$,the rate of reaction is given by:Rate $= -\frac{1}{X} \frac{d[A]}{dt} = -\frac{1}{Y} \frac{d[B]}{dt} = \frac{1}{Z} \frac{d[C]}{dt}$Given that $\frac{-d[A]}{dt} = \frac{-d[B]}{dt} = \frac{d[C]}{dt}$,we can equate these to the rate expression:$\frac{1}{X} (	ext{Rate}) = \frac{1}{Y} (	ext{Rate}) = \frac{1}{Z} (	ext{Rate})$This implies that $X = Y = Z$. Since the coefficients in a balanced chemical equation must be equal for the rates of disappearance and appearance to be equal,the simplest integer ratio is $X = Y = Z = 1$. However,looking at the options provided,the statement $X = Y = Z$ is implied by the equality of the rates. Given the options,the most consistent choice is that the coefficients are equal.

$t \ (s)$	$0$	$30$	$60$	$90$
$[\text{Ester}] \ (mol \ L^{-1})$	$0.55$	$0.31$	$0.17$	$0.085$

For the reaction,$XA + YB \rightarrow ZC$,if $\frac{- d [ A ]}{ dt } = \frac{- d [ B ]}{ dt } = \frac{d [ C ]}{ dt },$ then the correct statement among the following is:

Similar Questions

Thermal decomposition of $N_2O_5$ occurs as per the equation below:
$2N_2O_5 \longrightarrow 4NO_2 + O_2$
The correct statement is:

For the reaction $2A \rightarrow 3C + D$, the rate of reaction is represented by:

In a pseudo first order hydrolysis of ester in water,the following results were obtained:

$t \ (s)$ $0$ $30$ $60$ $90$

$[\text{Ester}] \ (mol \ L^{-1})$ $0.55$ $0.31$ $0.17$ $0.085$

What will be the average rate of reaction between the time interval $30 \ s$ to $60 \ s$?

What is the rate of reaction?

Assertion : The rate of the reaction is the rate of change of concentration of a reactant or a product.
Reason : Rate of reaction remains constant during the course of reaction.

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