For the reaction 2A + 3B to 4C,the rate of re | vedclass

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Question

(A) For a general chemical reaction $aA + bB 	o cC + dD$,the rate of reaction $(r)$ is given by the expression: $r = - \frac{1}{a} \frac{d[A]}{dt} =

Vedclass · Accepted Answer

$r = - \frac{1}{2} \frac{d[A]}{dt} = - \frac{1}{3} \frac{d[B]}{dt} = \frac{1}{4} \frac{d[C]}{dt}$

Vedclass · Answer

(A) For a general chemical reaction $aA + bB 	o cC + dD$,the rate of reaction $(r)$ is given by the expression: $r = - \frac{1}{a} \frac{d[A]}{dt} = - \frac{1}{b} \frac{d[B]}{dt} = \frac{1}{c} \frac{d[C]}{dt} = \frac{1}{d} \frac{d[D]}{dt}$ Given the reaction $2A + 3B 	o 4C$,we identify the stoichiometric coefficients as $a = 2$,$b = 3$,and $c = 4$. Substituting these values into the rate expression,we get: $r = - \frac{1}{2} \frac{d[A]}{dt} = - \frac{1}{3} \frac{d[B]}{dt} = \frac{1}{4} \frac{d[C]}{dt}$ Thus,option $A$ is the correct representation.

For the reaction $2A + 3B \to 4C$,the rate of reaction may be represented as:

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The rate of reaction is expressed as
$+\frac{1}{2}\frac{d[C]}{dt} = -\frac{1}{3}\frac{d[D]}{dt} = +\frac{1}{4}\frac{d[A]}{dt} = -\frac{d[B]}{dt}$
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