For the reaction,A + 3 B rightarrow 2 C,the r | vedclass

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(B) For the reaction $A + 3 B \rightarrow 2 C$,the rate of reaction is given by: $-\frac{d[A]}{dt} = -\frac{1}{3} \frac{d[B]}{dt} = \frac{1}{2} \frac{

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$4.2 \ mol \ dm^{-3} \ minute^{-1}$

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(B) For the reaction $A + 3 B ightarrow 2 C$,the rate of reaction is given by: $-\frac{d[A]}{dt} = -\frac{1}{3} \frac{d[B]}{dt} = \frac{1}{2} \frac{d[C]}{dt}$ Given that the rate of consumption of $A$ is $-\frac{d[A]}{dt} = 1.4 \ mol \ dm^{-3} \ minute^{-1}$. We need to find the rate of consumption of $B$,which is $-\frac{d[B]}{dt}$. From the rate expression: $-\frac{d[A]}{dt} = -\frac{1}{3} \frac{d[B]}{dt}$ Therefore,$-\frac{d[B]}{dt} = 3 	imes (-\frac{d[A]}{dt}) = 3 	imes 1.4 \ mol \ dm^{-3} \ minute^{-1} = 4.2 \ mol \ dm^{-3} \ minute^{-1}$.

For the reaction,$A + 3 B \rightarrow 2 C$,the rate of consumption of $A$ is $1.4 \ mol \ dm^{-3} \ minute^{-1}$. Calculate the rate of consumption of $B$.

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