For the refraction of light through a prism,w | vedclass

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(D) $1$. The angle of minimum deviation $\delta_m$ for a prism is given by $\delta_m = (n - 1)A$ for small angles,or more generally $\sin((A + \delta_

Vedclass · Accepted Answer

All of the above.

Vedclass · Answer

(D) $1$. The angle of minimum deviation $\delta_m$ for a prism is given by $\delta_m = (n - 1)A$ for small angles,or more generally $\sin((A + \delta_m)/2) = n \sin(A/2)$. As the refractive index $n$ (or $\mu_P$) increases,$\delta_m$ increases. Thus,statement $A$ is correct.$2$. For a prism set for minimum deviation,the ray inside the prism is parallel to the base of the prism. This is a standard property of minimum deviation. Thus,statement $B$ is correct.$3$. Maximum deviation occurs at the extreme angles of incidence,i.e.,$i = 0^\circ$ or $i = 90^\circ$. Since there are two such extreme boundaries,there are two angles of incidence that result in maximum deviation. Thus,statement $C$ is correct.$4$. Since all statements are correct,the correct option is $D$.

For the refraction of light through a prism,which of the following statements is correct?

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