For two events A and B,if P(A) = P(A|B) = 1/4 | vedclass

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(D) Given $P(B|A) = 1/2$,we have $P(B \cap A) / P(A) = 1/2$. Since $P(A) = 1/4$,$P(B \cap A) = (1/2) 	imes (1/4) = 1/8$.Given $P(A|B) = 1/4$,we have

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All of these

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(D) Given $P(B|A) = 1/2$,we have $P(B \cap A) / P(A) = 1/2$. Since $P(A) = 1/4$,$P(B \cap A) = (1/2) 	imes (1/4) = 1/8$.Given $P(A|B) = 1/4$,we have $P(A \cap B) / P(B) = 1/4$. Thus,$P(B) = P(A \cap B) / (1/4) = (1/8) / (1/4) = 1/2$.Since $P(A \cap B) = 1/8$ and $P(A) 	imes P(B) = (1/4) 	imes (1/2) = 1/8$,we have $P(A \cap B) = P(A)P(B)$,so $A$ and $B$ are independent.For independent events,$P(A'|B) = P(A') = 1 - P(A) = 1 - 1/4 = 3/4$.Also,$P(B'|A') = P(B') = 1 - P(B) = 1 - 1/2 = 1/2$.Therefore,all statements are correct.

For two events $A$ and $B$,if $P(A) = P(A|B) = 1/4$ and $P(B|A) = 1/2$,then

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