Force is the mutual interaction between the bodies according to:

$A$ ball of mass $60 \ g$ hits a wall with a velocity of $4 \ m/s$ and rebounds with the same velocity. The change in momentum in $kg \cdot m/s$ is:

$A$ particle of mass $2 \ kg$ is initially at rest. $A$ force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle after $10 \ s$ is $.... \ ms^{-1}$.

The figure shows the position-time graph of a particle of mass $4 \,kg$. What is the
$(a)$ force on the particle for $t < 0$,$t > 4 \,s$,and $0 < t < 4 \,s$?
$(b)$ impulse at $t = 0$ and $t = 4 \,s$? (Consider one-dimensional motion only).

$A$ body of mass $50 \, g$ has a velocity of $20 \, cm/s$. If a constant force of $50 \, dyne$ acts on it,what will be its momentum after $5 \, s$?

In a force $F$ versus time $t$ graph for an object,the area enclosed in a time interval of $1 \ s$ is $100 \ Ns$. Calculate the magnitude of the force. (in $N$)