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(D) Formaldehyde $(HCHO)$ and formic acid $(HCOOH)$ can be distinguished using sodium bicarbonate $(NaHCO_3)$.Formic acid reacts with sodium bicarbona

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Sodium bicarbonate

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(D) Formaldehyde $(HCHO)$ and formic acid $(HCOOH)$ can be distinguished using sodium bicarbonate $(NaHCO_3)$.Formic acid reacts with sodium bicarbonate to evolve carbon dioxide gas,which causes effervescence:$HCOOH + NaHCO_3 	o HCOONa + H_2O + CO_2 \uparrow$Formaldehyde does not react with sodium bicarbonate.Both formaldehyde and formic acid react with Tollen's reagent and Fehling solution,so they cannot be distinguished by these reagents.

Formaldehyde and formic acid can be distinguished using

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