Formaldehyde when treated with $KOH$ gives methanol and potassium formate. The reaction is known as

Reaction of ethyl formate with excess of $CH_3MgI$ followed by hydrolysis gives

The reagent$(s)$ which can be used to bring about the following transformation is(are):
$(A)$ $LiAlH_4$ in $(C_2H_5)_2O$
$(B)$ $BH_3$ in $THF$
$(C)$ $NaBH_4$ in $C_2H_5OH$
$(D)$ Raney $Ni / H_2$ in $THF$

In the Claisen-Schmidt reaction to prepare $351 \ g$ of dibenzalacetone using $87 \ g$ of acetone,the amount of benzaldehyde required is . . . . . . . $g$. (Nearest integer)

In the following reaction,
$CH_3-C \equiv CH$ $\xrightarrow[H_3O^+]{Hg^{2+}} X$ $\xrightarrow[PhCHO]{dil. NaOH} Y$
$X$ and $Y$,respectively,are

Which of the following compounds will not undergo an aldol condensation reaction?