Formation of $NO_{2(g)}$ from $N_{2(g)}$ and $O_{2(g)}$ is an endothermic process. Which of the following is true for this reaction?

  • A
    $\Delta H = 0$
  • B
    $\Delta H < 0$
  • C
    $\Delta H = \Delta U$
  • D
    $\Delta H > 0$

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Similar Questions

The enthalpy change for a reaction does not depend on:

The formation of ammonia is shown by the reaction $N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}, \Delta_r H^o = -91.8 \, kJ \, mol^{-1}$. What will be the enthalpy of reaction for the decomposition of $NH_3$ according to the reaction $2NH_{3(g)} \to N_{2(g)} + 3H_{2(g)}; \Delta_r H^o = ?$ ..... $kJ \, mol^{-1}$

Use the data from the table to estimate the enthalpy of formation of $CH_3CHO$.
BondBond Enthalpy $(kJ \ mol^{-1})$Enthalpy of formation $(kJ \ mol^{-1})$
$C-H$$400$$C(g): 700$
$C-C$$350$$H(g): 200$
$C=O$$700$$O(g): 250$

Calculate $\Delta_r H$ $(kJ \ mol^{-1})$ of the following reaction:
$C_2H_5OH_{(l)} + \frac{7}{2}O_{2(g)} \rightarrow 2CO_{2(g)} + 3H_2O_{(l)}$
Molecule$\Delta_f H^0 (kJ \ mol^{-1})$
$C_2H_5OH_{(l)}$$-280$
$CO_{2(g)}$$-400$
$H_2O_{(l)}$$-290$

Calculate the enthalpy of formation of nitric oxide $(NO)$ in $kJ \, mol^{-1}$ from the following data:
$NO_{(g)} + CO_{(g)} \rightarrow \frac{1}{2} N_{2(g)} + CO_{2(g)}; \Delta H^o = -372.2 \, kJ \, mol^{-1}$
$\Delta H_f^o (CO) = -110.5 \, kJ \, mol^{-1}$
$\Delta H_f^o (CO_2) = -393.5 \, kJ \, mol^{-1}$

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