(D) In ferric sulphate,the iron ion is in the $+3$ oxidation state,represented as $Fe^{3+}$.The sulphate ion has a charge of $-2$,represented as $SO_4

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(D) In ferric sulphate,the iron ion is in the $+3$ oxidation state,represented as $Fe^{3+}$.The sulphate ion has a charge of $-2$,represented as $SO_4^{2-}$.To balance the charges,we need two $Fe^{3+}$ ions $(2 \times +3 = +6)$ and three $SO_4^{2-}$ ions $(3 \times -2 = -6)$.Therefore,the chemical formula is $Fe_2(SO_4)_3$.