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(C) When four coins are tossed,the total number of possible outcomes is $2^4 = 16$.The event of getting 'at least one head' is the complement of the e

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$15/16$

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(C) When four coins are tossed,the total number of possible outcomes is $2^4 = 16$.The event of getting 'at least one head' is the complement of the event of getting 'no head' (i.e.,all tails).The probability of getting no head is $P(	ext{no head}) = \frac{1}{16}$.Therefore,the probability of getting at least one head is $P(	ext{at least one head}) = 1 - P(	ext{no head})$.$P(	ext{at least one head}) = 1 - \frac{1}{16} = \frac{15}{16}$.

Four coins are tossed. The probability that at least one head turns up is

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