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(C) The circuit consists of a capacitor in series with two parallel capacitors,all of which are in parallel with a fourth capacitor.$1$. First,conside

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$\frac{5}{3}\,C$

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(C) The circuit consists of a capacitor in series with two parallel capacitors,all of which are in parallel with a fourth capacitor.$1$. First,consider the two capacitors connected in parallel. Their equivalent capacitance is $C_p = C + C = 2C$.$2$. This combination is in series with the third capacitor of capacitance $C$. The equivalent capacitance of this series branch is $C_s = \frac{C 	imes 2C}{C + 2C} = \frac{2C^2}{3C} = \frac{2}{3}C$.$3$. Finally,this branch is in parallel with the fourth capacitor of capacitance $C$. The total effective capacitance between $A$ and $B$ is $C_{AB} = C_s + C = \frac{2}{3}C + C = \frac{5}{3}C$.

Four equal capacitors,each of capacity $C$,are arranged as shown. The effective capacitance between $A$ and $B$ is

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