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(B) Since all four capacitors are identical and connected in series,the potential difference across each capacitor is equal.Total potential difference

Vedclass · Accepted Answer

$7.5\,V, -2.5\,V$

Vedclass · Answer

(B) Since all four capacitors are identical and connected in series,the potential difference across each capacitor is equal.Total potential difference $V = 10\,V$.Potential difference across each capacitor $= 10\,V / 4 = 2.5\,V$.Point $N$ is earthed,so its potential $V_N = 0\,V$.Moving from $A$ to $N$,there are three capacitors in series. The potential drop across these three capacitors is $3 	imes 2.5\,V = 7.5\,V$.Thus,$V_A - V_N = 7.5\,V \Rightarrow V_A - 0 = 7.5\,V \Rightarrow V_A = 7.5\,V$.Moving from $N$ to $B$,there is one capacitor. The potential drop across this capacitor is $2.5\,V$.Since we are moving from the positive terminal side towards the negative terminal side of the battery,the potential decreases.Thus,$V_N - V_B = 2.5\,V \Rightarrow 0 - V_B = 2.5\,V \Rightarrow V_B = -2.5\,V$.

Four identical capacitors are connected in series with a $10\,V$ battery as shown. The point $N$ is earthed. The potentials of points $A$ and $B$ are

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