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(A) The magnification $M$ of an astronomical telescope is given by the formula $M = -\frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective

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$15$

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(A) The magnification $M$ of an astronomical telescope is given by the formula $M = -\frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.To obtain the largest magnification,the ratio $\left| \frac{f_o}{f_e} \right|$ must be maximized.This requires the objective lens to have the largest focal length $(f_o = 150\; cm)$ and the eyepiece to have the smallest focal length $(f_e = 15\; cm)$.Thus,the focal length of the eyepiece should be $15\; cm$.

Four lenses of focal length $\pm 15\; cm$ and $\pm 150 \;cm$ are available for making a telescope. To produce the largest magnification,the focal length (in $cm$) of the eyepiece should be

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