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(B) The given arrangement consists of four parallel plates. Let the plates be numbered $1, 2, 3, 4$ from top to bottom.Plate $1$ and $3$ are connected

Vedclass · Accepted Answer

$\frac{3{\varepsilon _0}A}{d}$

Vedclass · Answer

(B) The given arrangement consists of four parallel plates. Let the plates be numbered $1, 2, 3, 4$ from top to bottom.Plate $1$ and $3$ are connected to point $A$,and plate $2$ and $4$ are connected to point $B$.This forms three capacitors in parallel between points $A$ and $B$.However,looking at the diagram,the connections show that there are $3$ gaps between the $4$ plates.Specifically,the arrangement creates $3$ capacitors in parallel,each with capacitance $C = \frac{{\varepsilon _0}A}{d}$.Thus,the equivalent capacitance is $C_{eq} = C + C + C = \frac{3{\varepsilon _0}A}{d}$.

Four plates of equal area $A$ are separated by equal distances $d$ and are arranged as shown in the figure. The equivalent capacity is

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