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(C) Let the present age of the mother be $M$ and the present ages of the two daughters be $D_1$ and $D_2$.Four years ago,the sum of their ages was $(M

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$x+18$

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(C) Let the present age of the mother be $M$ and the present ages of the two daughters be $D_1$ and $D_2$.Four years ago,the sum of their ages was $(M-4) + (D_1-4) + (D_2-4) = x$.This simplifies to $M + D_1 + D_2 - 12 = x$,which means the current sum of their ages is $M + D_1 + D_2 = x + 12$.We need to find the sum of their ages after two years,which is $(M+2) + (D_1+2) + (D_2+2)$.This expression equals $(M + D_1 + D_2) + 6$.Substituting the current sum $(x + 12)$ into this expression,we get $(x + 12) + 6 = x + 18$.Therefore,the sum of their ages after two years will be $x + 18$ years.

Four years ago,the sum of the ages of a mother and her two daughters was $x$ years. What will be the sum of their ages after two years?

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