From a class of 12 girls and 18 boys,two stud | vedclass

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Question

(A) Total number of students = $12 + 18 = 30$.Number of ways to choose $2$ students from $30$ is given by $^{30}C_2 = \frac{30 	imes 29}{2 	imes 1}

Vedclass · Accepted Answer

$\frac{22}{145}$

Vedclass · Answer

(A) Total number of students = $12 + 18 = 30$.Number of ways to choose $2$ students from $30$ is given by $^{30}C_2 = \frac{30 	imes 29}{2 	imes 1} = 435$.Number of ways to choose $2$ girls from $12$ is given by $^{12}C_2 = \frac{12 	imes 11}{2 	imes 1} = 66$.The probability that both chosen students are girls is $P = \frac{^{12}C_2}{^{30}C_2} = \frac{66}{435}$.Dividing both numerator and denominator by $3$,we get $P = \frac{22}{145}$.

From a class of $12$ girls and $18$ boys,two students are chosen randomly. What is the probability that both of them are girls?

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