According to Kirchhoff's law,the ratio of emi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Kirchhoff's law of radiation states that for an arbitrary body emitting and absorbing thermal radiation in thermodynamic equilibrium,the ratio of

Vedclass · Accepted Answer

Equal to the emissive power of a black body at the same temperature.

Vedclass · Answer

(B) Kirchhoff's law of radiation states that for an arbitrary body emitting and absorbing thermal radiation in thermodynamic equilibrium,the ratio of its emissive power $(E)$ to its absorptive power $(a)$ is equal to the emissive power of a perfect black body $(E_b)$ at the same temperature.Mathematically,this is expressed as: $\frac{E}{a} = E_b$.Therefore,the ratio is equal to the emissive power of a black body at the same temperature.

According to Kirchhoff's law,the ratio of emissive power to absorptive power for all bodies is:

Similar Questions

About black body radiation, which one of the following is a $WRONG$ statement?

The rate of emission of a body doubles when its temperature is increased by $10^{\circ}C$. If the temperature of the body is increased from $10^{\circ}C$ to $100^{\circ}C$,the rate of emission increases by a factor of:

Regarding black body radiation,which one of the following is the $WRONG$ statement?

Which of the following is best close to an ideal black body?

Three objects colored black,gray,and white can withstand hostile conditions up to $2800\,^oC$. These objects are thrown into a furnace where each of them attains a temperature of $2000\,^oC$. Which object will glow brightest?

Vedclass Test Series

Exam Paper Generator

Online Exam Module