From the following masses,the one which is ex | vedclass

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(C) The precision of a measurement is determined by the number of decimal places.$1 \ g = 1000 \ mg$,which means $0.001 \ g = 1 \ mg$.To express a mas

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$16.428$

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(C) The precision of a measurement is determined by the number of decimal places.$1 \ g = 1000 \ mg$,which means $0.001 \ g = 1 \ mg$.To express a mass nearest to the milligram,the value must be measured up to three decimal places (i.e.,the thousandths place in grams).Comparing the options:$16 \ g$ has $0$ decimal places.$16.4 \ g$ has $1$ decimal place.$16.428 \ g$ has $3$ decimal places,which corresponds to the milligram precision $(16428 \ mg)$.$16.4284 \ g$ has $4$ decimal places,which is more precise than the milligram level.Therefore,$16.428 \ g$ is the value expressed nearest to the milligram.

From the following masses,the one which is expressed nearest to the milligram is (in $g$)

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