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(C) We are given the following thermochemical equations:$(1) HA 	o A^{-} + H^{+} , \Delta H = Z$$(2) H^{+} + OH^{-} 	o H_2O , \Delta H = X$$(3) HA +

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$Y - X$

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(C) We are given the following thermochemical equations:$(1) HA 	o A^{-} + H^{+} , \Delta H = Z$$(2) H^{+} + OH^{-} 	o H_2O , \Delta H = X$$(3) HA + OH^{-} 	o A^{-} + H_2O , \Delta H = Y$According to Hess's Law,we can obtain equation $(3)$ by adding equation $(1)$ and equation $(2)$:$(HA 	o A^{-} + H^{+}) + (H^{+} + OH^{-} 	o H_2O) 	o HA + OH^{-} 	o A^{-} + H_2O$Therefore,the enthalpy change for equation $(3)$ is the sum of the enthalpy changes of equations $(1)$ and $(2)$:$Y = Z + X$Rearranging to solve for $Z$:$Z = Y - X$

From the following thermochemical equations,find out the heat of ionisation $Z$ for a weak acid $HA$:
$HA \to A^{-} + H^{+} , \Delta H = Z$
$H^{+} + OH^{-} \to H_2O , \Delta H = X$
$HA + OH^{-} \to A^{-} + H_2O , \Delta H = Y$

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From the following thermochemical equations,find out the heat of ionisation $Z$ for a weak acid $HA$:$HA \to A^{-} + H^{+} , \Delta H = Z$$H^{+} + OH^{-} \to H_2O , \Delta H = X$$HA + OH^{-} \to A^{-} + H_2O , \Delta H = Y$