From the magnetic behaviour of [NiCl_4]^{2-} | vedclass

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(B) For $[NiCl_4]^{2-}$: The oxidation state of $Ni$ is $+2$. The electronic configuration is $[Ar] 3d^8$. Due to the weak field ligand $Cl^-$,it unde

Vedclass · Accepted Answer

$[NiCl_4]^{2-}: Ni^{II}$,tetrahedral; $[Ni(CO)_4]: Ni(0)$,tetrahedral

Vedclass · Answer

(B) For $[NiCl_4]^{2-}$: The oxidation state of $Ni$ is $+2$. The electronic configuration is $[Ar] 3d^8$. Due to the weak field ligand $Cl^-$,it undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry with $2$ unpaired electrons,making it paramagnetic.For $[Ni(CO)_4]$: The oxidation state of $Ni$ is $0$. The electronic configuration is $[Ar] 3d^8 4s^2$. In the presence of the strong field ligand $CO$,the electrons pair up to form $[Ar] 3d^{10} 4s^0$. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry with $0$ unpaired electrons,making it diamagnetic.

List-$I$ (Complex)	List-$II$ (Hybridization)
$A. Ni(CO)_4$	$I. sp^3d^2$
$B. [Ni(CN)_4]^{2-}$	$II. d^2sp^3$
$C. [Co(NH_3)_6]^{3+}$	$III. dsp^2$
$D. [CoF_6]^{3-}$	$IV. sp^3$

List-$I$	List-$II$
$(1)$ $dsp^2$	$(A)$ $BrF_5$
$(2)$ $sp^3d^2$	$(B)$ $[Co(NH_3)_6]^{3+}$
$(3)$ $sp^3d$	$(C)$ $[PtCl_4]^{2-}$
$(4)$ $d^2sp^3$	$(D)$ $PCl_5$

From the magnetic behaviour of $[NiCl_4]^{2-}$ (paramagnetic) and $[Ni(CO)_4]$ (diamagnetic),choose the correct geometry and oxidation state.

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Which set of $d-$ orbitals is used by the central metal during the formation of $MnO_4^-$?

Match the complexes in List-$I$ with their hybridization in List-$II$.
List-$I$ (Complex) List-$II$ (Hybridization)
$A. Ni(CO)_4$ $I. sp^3d^2$
$B. [Ni(CN)_4]^{2-}$ $II. d^2sp^3$
$C. [Co(NH_3)_6]^{3+}$ $III. dsp^2$
$D. [CoF_6]^{3-}$ $IV. sp^3$

Match the type of hybridization given in List-$I$ with the molecules/ions given in List-$II$.

List-$I$ List-$II$

$(1)$ $dsp^2$ $(A)$ $BrF_5$

$(2)$ $sp^3d^2$ $(B)$ $[Co(NH_3)_6]^{3+}$

$(3)$ $sp^3d$ $(C)$ $[PtCl_4]^{2-}$

$(4)$ $d^2sp^3$ $(D)$ $PCl_5$

The complex $[Ag(NH_3)_2]^{+}$ has $sp$ hybridization and is a ...... complex.

Dimethyl glyoxime forms a square planar complex with $Ni^{2+}$. This complex should be

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