From the positions in the original figure,A a | vedclass

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(C) $1$. Initial positions: $A$ is at south-west,$B$ is at north-east,$C$ is at north-west,and $D$ is at south-east.$2$. $A$ moves diagonally to the o

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At the south-east corner

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(C) $1$. Initial positions: $A$ is at south-west,$B$ is at north-east,$C$ is at north-west,and $D$ is at south-east.$2$. $A$ moves diagonally to the opposite corner (north-east) and then one side clockwise,which brings it to the south-east corner.$3$. $C$ moves diagonally to the opposite corner (south-east) and then one side anticlockwise,which brings it to the north-east corner.$4$. $D$ moves two sides clockwise,which brings it to the north-east corner.$5$. $B$ moves two sides anticlockwise,which brings it to the south-west corner.$6$. Therefore,$A$ is now at the south-east corner.

From the positions in the original figure,$A$ and $C$ move diagonally to opposite corners and then one side each clockwise and anticlockwise respectively. $D$ and $B$ move two sides each clockwise and anticlockwise respectively. Where is $A$ now?

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