From the velocity-time graph of a particle mo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The graph shows a straight line with a positive slope,which means the acceleration $a = \frac{dv}{dt}$ is constant. Since $F = ma$,a constant acce

Vedclass · Accepted Answer

The speed of the particle increases continuously.

Vedclass · Answer

(B) The graph shows a straight line with a positive slope,which means the acceleration $a = \frac{dv}{dt}$ is constant. Since $F = ma$,a constant acceleration implies a constant force.As the particle moves,its velocity changes from negative to positive. The area under the $v-t$ graph represents displacement. Since the graph crosses the time axis,the net displacement can become zero,meaning the particle crosses its initial position.However,the speed is the magnitude of velocity $|v|$. As the particle moves from a negative velocity towards zero and then to positive values,its speed first decreases (as it approaches zero) and then increases. Therefore,the statement that the speed increases continuously is incorrect.

From the velocity-time graph of a particle moving in a straight line,decide which of the following is an incorrect statement.

Similar Questions

The figure shows a velocity-time graph of a particle moving along a straight line. If the particle starts from the position $x_0 = -15 \, m$,then its position at $t = 2 \, s$ will be ........ $m$.

The acceleration-time graph of a body is shown below. The most probable velocity-time graph of the body is:

For an object moving on a straight line,draw $x-t$ graphs for:
$(i)$ When it is at rest.
$(ii)$ When it is moving with constant velocity in the positive direction.
$(iii)$ When it is moving with constant velocity in the negative direction.
$(iv)$ When it performs non-uniform motion.

$Assertion$ : Velocity-time graph for an object in uniform motion along a straight path is a straight line parallel to the time axis.
$Reason$ : In uniform motion of an object velocity increases as the square of time elapsed.

Two cars $P$ and $Q$ start from a point at the same time in a straight line and their positions are represented by $x_P(t) = at + bt^2$ and $x_Q(t) = ft - t^2$. At what time do the cars have the same velocity?

Vedclass Test Series

Exam Paper Generator

Online Exam Module