From which solution 2 F electrical charge wi | vedclass

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(D) According to Faraday's law of electrolysis,the amount of substance deposited is given by $W = \frac{Z 	imes I 	imes t}{96500} = \frac{M 	imes Q

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Calcium sulphate

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(D) According to Faraday's law of electrolysis,the amount of substance deposited is given by $W = \frac{Z 	imes I 	imes t}{96500} = \frac{M 	imes Q}{n 	imes F}$,where $n$ is the valency of the metal ion.Given that $Q = 2 \ F$ and the mass deposited $W = 1 	imes 	ext{atomic weight} (M)$.Substituting these values: $M = \frac{M 	imes 2 \ F}{n 	imes F} \implies 1 = \frac{2}{n} \implies n = 2$.This means the metal ion must have a valency of $2$.In $CaSO_4$,the calcium ion is $Ca^{2+}$,which has a valency of $2$.

From which solution $2 \ F$ electrical charge will deposit $1 \ g$ atomic weight at cathode?

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