Fusion of MnO_2 with KOH in presence of O_2 p | vedclass

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(B) $MnO_2 + 2 KOH + \frac{1}{2} O_2 \xrightarrow{\Delta} K_2MnO_4 + H_2O$ $(W)$$W = K_2MnO_4 \rightleftharpoons 2K^{\oplus} + MnO_4^{2-} (Y)$$K_2MnO_

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$2, 3, 4$

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(B) $MnO_2 + 2 KOH + \frac{1}{2} O_2 \xrightarrow{\Delta} K_2MnO_4 + H_2O$ $(W)$$W = K_2MnO_4 ightleftharpoons 2K^{\oplus} + MnO_4^{2-} (Y)$$K_2MnO_4 + H_2O \xrightarrow{	ext{Electrolytic}} H_2 + KOH + KMnO_4 (X)$Anion of $X = MnO_4^{-} (Z)$$1$. $Y$ $(MnO_4^{2-})$ is $d^1$ (paramagnetic) and $Z$ $(MnO_4^{-})$ is $d^0$ (diamagnetic). Statement $(1)$ is incorrect.$2$. Both $MnO_4^{2-}$ and $MnO_4^{-}$ are coloured due to charge transfer and have tetrahedral geometry. Statement $(2)$ is correct.$3$. In both,$\pi$-bonding occurs between $p$-orbitals of oxygen and $d$-orbitals of manganese ($p\pi-d\pi$ bonding). Statement $(3)$ is correct.$4$. In acidic solution,$MnO_4^{2-}$ undergoes disproportionation: $3MnO_4^{2-} + 4H^{\oplus} \longrightarrow 2MnO_4^{-} + MnO_2 + 2H_2O$. Statement $(4)$ is correct.Thus,statements $(2, 3, 4)$ are correct.

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