Gases possess characteristic critical temperature which depends upon the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases:
$Gases$ $Critical \ temperature \ in \ Kelvin$ $P$ $33.2$ $Q$ $5.3$ $R$ $154.3$ $S$ $126$
From the above data,what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first.
| $Gases$ | $Critical \ temperature \ in \ Kelvin$ |
| $P$ | $33.2$ |
| $Q$ | $5.3$ |
| $R$ | $154.3$ |
| $S$ | $126$ |
From the above data,what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first.
- A$P, Q, R, S$
- B$Q, R, P, S$
- C$R, S, P, Q$
- D$S, R, Q, P$
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$A.$ Carbon dioxide remains as a gas up to point $(b)$
$B.$ Liquid carbon dioxide appears at point $(c)$
$C.$ Liquid and gaseous carbon dioxide coexist between points $(b)$ and $(c)$
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$A.$ Carbon dioxide remains as a gas up to point $(b)$
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$D.$ As the volume decreases from $(b)$ to $(c)$,the amount of liquid decreases
The critical temperatures $(T_C)$ of some gases are given below:
Gases $H_2, He, O_2$ $T_C \ (K)$ $33.2, 5.3, 154.3$
Based on the above data,what is the order of liquefaction of these gases? Start writing the order from the gas that liquefies first.
| Gases | $H_2, He, O_2$ |
| $T_C \ (K)$ | $33.2, 5.3, 154.3$ |
Based on the above data,what is the order of liquefaction of these gases? Start writing the order from the gas that liquefies first.
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