Gauss's law states that
- Athe total electric flux through a closed surface is $\frac{1}{\varepsilon_0}$ times the total charge placed near the closed surface.
- Bthe total electric flux through a closed surface is $\frac{1}{\varepsilon_0}$ times the total charge enclosed by the closed surface.
- Cthe total electric flux through an open surface is $\frac{1}{\varepsilon_0}$ times the total charge placed near the open surface.
- Dthe line integral of electric field around the boundary of an open surface is $\frac{1}{\varepsilon_0}$ times the total charge placed near the open surface.
Explore More
Similar Questions
Consider the charges and the Gaussian surface shown in the figure. When calculating the electric flux through the spherical surface,the electric field is due to which of the following?
Medium
View Solution$A$ charge $q$ is placed at the centre of the open end of a cylindrical vessel. The flux of the electric field through the surface of the vessel is
Easy
View SolutionTwo equations are given below:
$A. \oint E \cdot dA = \frac{Q}{\varepsilon_0}$
$B. \oint B \cdot dA = 0$
They are:
$A. \oint E \cdot dA = \frac{Q}{\varepsilon_0}$
$B. \oint B \cdot dA = 0$
They are:
$A$ positive charge $q$ is kept at the center of a thick shell of inner radius $R_1$ and outer radius $R_2$ which is made up of conducting material. If $\phi_1$ is the flux through a closed Gaussian surface $S_1$ whose radius is just less than $R_1$ and $\phi_2$ is the flux through a closed Gaussian surface $S_2$ whose radius is just greater than $R_1$,then:
Medium
View SolutionIf charge $q$ is placed on one of the vertex of a cube, then total electric flux passing through the cube is . . . . . . .
MediumGUJCET 2026
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo