Give the conversion of the following:
$(i)$ Lactic acid from ethanal
$(ii)$ $p-$fluorobenzaldehyde from $p-$fluorotoluene
$(i)$ Lactic acid from ethanal
$(ii)$ $p-$fluorobenzaldehyde from $p-$fluorotoluene
(N/A) $(i)$ Conversion of ethanal to lactic acid:
$CH_3CHO + HCN$ $\rightarrow CH_3CH(OH)CN$ $\xrightarrow{H_3O^+} CH_3CH(OH)COOH$ (Lactic acid)
$(ii)$ Conversion of $p-$fluorotoluene to $p-$fluorobenzaldehyde:
$p-F-C_6H_4-CH_3$ $\xrightarrow[273-278 \ K]{CrO_3, (CH_3CO)_2O} p-F-C_6H_4-CH(OCOCH_3)_2$ $\xrightarrow{H_3O^+} p-F-C_6H_4-CHO$ ($p-$fluorobenzaldehyde)
$CH_3CHO + HCN$ $\rightarrow CH_3CH(OH)CN$ $\xrightarrow{H_3O^+} CH_3CH(OH)COOH$ (Lactic acid)
$(ii)$ Conversion of $p-$fluorotoluene to $p-$fluorobenzaldehyde:
$p-F-C_6H_4-CH_3$ $\xrightarrow[273-278 \ K]{CrO_3, (CH_3CO)_2O} p-F-C_6H_4-CH(OCOCH_3)_2$ $\xrightarrow{H_3O^+} p-F-C_6H_4-CHO$ ($p-$fluorobenzaldehyde)
Explore More
Similar Questions
Enumerate different methods to prepare aldehyde compounds.
Medium
View SolutionIn which of the following reactions is benzaldehyde formed from benzoyl chloride and hydrogen in the presence of $Pd-BaSO_4$?
In the Rosenmund's reduction,$BaSO_4$ taken with catalyst $Pd$ acts as
Medium
View SolutionThe major product formed in the following reaction scheme is
DifficultTS EAMCET 2021
View SolutionMatch List-$I$ with List-$II$:
List-$I$ List-$II$ $A$. $RCN \xrightarrow[(ii) H_3O^+]{(i) SnCl_2, HCl} RCHO$ $I$. Etard reaction $B$. $C_6H_5COCl \xrightarrow{H_2, Pd-BaSO_4} C_6H_5CHO$ $II$. Gatterman-Koch reaction $C$. $C_6H_5CH_3 \xrightarrow[(ii) H_3O^+]{(i) CrO_2Cl_2, CS_2} C_6H_5CHO$ $III$. Rosenmund reduction $D$. $C_6H_6 \xrightarrow[(ii) \text{anhydrous } AlCl_3/CuCl]{(i) CO, HCl} C_6H_5CHO$ $IV$. Stephen reaction
Choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
|---|---|
| $A$. $RCN \xrightarrow[(ii) H_3O^+]{(i) SnCl_2, HCl} RCHO$ | $I$. Etard reaction |
| $B$. $C_6H_5COCl \xrightarrow{H_2, Pd-BaSO_4} C_6H_5CHO$ | $II$. Gatterman-Koch reaction |
| $C$. $C_6H_5CH_3 \xrightarrow[(ii) H_3O^+]{(i) CrO_2Cl_2, CS_2} C_6H_5CHO$ | $III$. Rosenmund reduction |
| $D$. $C_6H_6 \xrightarrow[(ii) \text{anhydrous } AlCl_3/CuCl]{(i) CO, HCl} C_6H_5CHO$ | $IV$. Stephen reaction |
Choose the correct answer from the options given below:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo