Give the conversion of the following:
$(i)$ $but-2-enal$ from $ethanal$
$(ii)$ $Methyl$ $benzoate$ from $benzaldehyde$
$(i)$ $but-2-enal$ from $ethanal$
$(ii)$ $Methyl$ $benzoate$ from $benzaldehyde$
(N/A) $(i)$ $But-2-enal$ from $ethanal$:
$2CH_3CHO$ $\xrightarrow{dil. NaOH} CH_3-CH(OH)-CH_2-CHO$ $\xrightarrow{\Delta, -H_2O} CH_3-CH=CH-CHO$
$Ethanal$ undergoes aldol condensation in the presence of dilute $NaOH$ to form $3-hydroxybutanal$ (aldol),which upon heating loses a water molecule to form $but-2-enal$.
$(ii)$ $Methyl$ $benzoate$ from $benzaldehyde$:
$C_6H_5CHO$ $\xrightarrow{[O]} C_6H_5COOH$ $\xrightarrow{CH_3OH, conc. H_2SO_4, \Delta} C_6H_5COOCH_3$
$Benzaldehyde$ is first oxidized to $benzoic$ $acid$ using an oxidizing agent like $KMnO_4$ or $Tollens'$ reagent. Then,$benzoic$ $acid$ undergoes Fischer esterification with $methanol$ in the presence of concentrated $H_2SO_4$ to yield $methyl$ $benzoate$.
$2CH_3CHO$ $\xrightarrow{dil. NaOH} CH_3-CH(OH)-CH_2-CHO$ $\xrightarrow{\Delta, -H_2O} CH_3-CH=CH-CHO$
$Ethanal$ undergoes aldol condensation in the presence of dilute $NaOH$ to form $3-hydroxybutanal$ (aldol),which upon heating loses a water molecule to form $but-2-enal$.
$(ii)$ $Methyl$ $benzoate$ from $benzaldehyde$:
$C_6H_5CHO$ $\xrightarrow{[O]} C_6H_5COOH$ $\xrightarrow{CH_3OH, conc. H_2SO_4, \Delta} C_6H_5COOCH_3$
$Benzaldehyde$ is first oxidized to $benzoic$ $acid$ using an oxidizing agent like $KMnO_4$ or $Tollens'$ reagent. Then,$benzoic$ $acid$ undergoes Fischer esterification with $methanol$ in the presence of concentrated $H_2SO_4$ to yield $methyl$ $benzoate$.
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Similar Questions
$A$ carbonyl compound $P$,which gives a positive iodoform test,undergoes reaction with $MeMgBr$ followed by dehydration to give an olefin $Q$. Ozonolysis of $Q$ leads to a dicarbonyl compound $R$,which undergoes intramolecular aldol reaction to give predominantly $S$.
$P$ $\xrightarrow[\substack{2. H^{+}, H_2 O \\ 3. H_2 SO_4, \Delta}]{1. MeMgBr} Q$ $\xrightarrow[2. Zn, H_2 O]{1. O_3} R$ $\xrightarrow[2. \Delta]{1. OH^{-}} S$
$1.$ The structure of the carbonyl compound $P$ is
$2.$ The structures of the products $Q$ and $R$,respectively,are
$3.$ The structure of the product $S$ is
Give the answer for questions $1, 2$ and $3.$
$P$ $\xrightarrow[\substack{2. H^{+}, H_2 O \\ 3. H_2 SO_4, \Delta}]{1. MeMgBr} Q$ $\xrightarrow[2. Zn, H_2 O]{1. O_3} R$ $\xrightarrow[2. \Delta]{1. OH^{-}} S$
$1.$ The structure of the carbonyl compound $P$ is
$2.$ The structures of the products $Q$ and $R$,respectively,are
$3.$ The structure of the product $S$ is
Give the answer for questions $1, 2$ and $3.$
DifficultIIT 2009
View SolutionWhich among the following compounds give a yellow solid when reacted with $NaOI/NaOH$? Choose the correct answer from the options given below $:$
$(A)$ $CH_3-CH(OH)-C_2H_5$
$(B)$ $CH_3-CH_2-CH_2-OH$
$(C)$ $CH_3-CO-C_2H_5$
$(D)$ $CH_3-COOH$
$(E)$ $CH_3-CH_2-CHO$
$(A)$ $CH_3-CH(OH)-C_2H_5$
$(B)$ $CH_3-CH_2-CH_2-OH$
$(C)$ $CH_3-CO-C_2H_5$
$(D)$ $CH_3-COOH$
$(E)$ $CH_3-CH_2-CHO$
Match the following reactions in Column-$1$ with their products in Column-$2$.
Column-$1$ (Reaction) Column-$2$ (Product) $A$. Benzaldehyde + $Zn-Hg/HCl$ $I$. Cyclohexanol $B$. Benzoyl chloride + $H_2/Pd-BaSO_4$ $II$. Benzyl alcohol $C$. Cyclohexanone + $NH_2NH_2/KOH$ $III$. Toluene $IV$. Benzaldehyde $V$. Cyclohexane
The correct match is:
| Column-$1$ (Reaction) | Column-$2$ (Product) |
| $A$. Benzaldehyde + $Zn-Hg/HCl$ | $I$. Cyclohexanol |
| $B$. Benzoyl chloride + $H_2/Pd-BaSO_4$ | $II$. Benzyl alcohol |
| $C$. Cyclohexanone + $NH_2NH_2/KOH$ | $III$. Toluene |
| $IV$. Benzaldehyde | |
| $V$. Cyclohexane |
The correct match is:
DifficultTS EAMCET 2021
View SolutionWhich of the following compounds responds to both iodoform test and Fehling's test?
Medium
View SolutionThe final product of the following reaction contains:
$CH_3 - C \equiv C - CH_2 - COCl \xrightarrow[BaSO_4]{H_2 - Pd}$
$CH_3 - C \equiv C - CH_2 - COCl \xrightarrow[BaSO_4]{H_2 - Pd}$
Difficult
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