Provide the chemical conversion for the following:
$(i)$ $3-$phenylprop$-2-$enal from Benzaldehyde and Ethanal (Cross-Aldol Condensation).
$(ii)$ Benzyl alcohol from Benzene.
$(i)$ $3-$phenylprop$-2-$enal from Benzaldehyde and Ethanal (Cross-Aldol Condensation).
$(ii)$ Benzyl alcohol from Benzene.
(N/A) $(i)$ $3-$phenylprop$-2-$enal is prepared by the cross-aldol condensation of Benzaldehyde $(C_6H_5CHO)$ and Ethanal $(CH_3CHO)$ in the presence of dilute $NaOH$ followed by dehydration.
$C_6H_5CHO + CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} C_6H_5CH(OH)CH_2CHO$ $\xrightarrow{\Delta, -H_2O} C_6H_5CH=CHCHO$
$(ii)$ Benzyl alcohol is prepared from Benzene in two steps:
$1.$ Gattermann-Koch reaction of Benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ and $CuCl$ to form Benzaldehyde.
$2.$ Cannizzaro reaction of Benzaldehyde with concentrated $NaOH$ to form Benzyl alcohol and Sodium benzoate.
$C_6H_6$ $\xrightarrow{CO, HCl, \text{anhydrous } AlCl_3, CuCl} C_6H_5CHO$ $\xrightarrow{\text{conc. } NaOH, \Delta} C_6H_5CH_2OH + C_6H_5COONa$
$C_6H_5CHO + CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} C_6H_5CH(OH)CH_2CHO$ $\xrightarrow{\Delta, -H_2O} C_6H_5CH=CHCHO$
$(ii)$ Benzyl alcohol is prepared from Benzene in two steps:
$1.$ Gattermann-Koch reaction of Benzene with $CO$ and $HCl$ in the presence of anhydrous $AlCl_3$ and $CuCl$ to form Benzaldehyde.
$2.$ Cannizzaro reaction of Benzaldehyde with concentrated $NaOH$ to form Benzyl alcohol and Sodium benzoate.
$C_6H_6$ $\xrightarrow{CO, HCl, \text{anhydrous } AlCl_3, CuCl} C_6H_5CHO$ $\xrightarrow{\text{conc. } NaOH, \Delta} C_6H_5CH_2OH + C_6H_5COONa$
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Identify appropriate reagents for the above reaction.
Choose the reactant whose aldol reaction would give jasmone.
Identify the name of the reaction in which the carbonyl group of aldehydes and ketones is reduced to a methylene group upon treatment with hydrazine,followed by heating with sodium hydroxide in ethylene glycol.
Match the reactions given in column-$I$ with the suitable reagents given in column-$II$.
Column-$I$ (Reactions) Column-$II$ (Reagents) $(i)$. Benzophenone $\rightarrow$ Diphenylmethane $(a)$. $LiAlH_4$ $(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol $(b)$. $DIBAL-H$ $(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol $(c)$. $Zn(Hg) / \text{Conc. } HCl$ $(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde $(d)$. $CH_3MgBr, H_2O$
| Column-$I$ (Reactions) | Column-$II$ (Reagents) |
| $(i)$. Benzophenone $\rightarrow$ Diphenylmethane | $(a)$. $LiAlH_4$ |
| $(ii)$. Benzaldehyde $\rightarrow$ $1-$Phenylethanol | $(b)$. $DIBAL-H$ |
| $(iii)$. Cyclohexanone $\rightarrow$ Cyclohexanol | $(c)$. $Zn(Hg) / \text{Conc. } HCl$ |
| $(iv)$. Phenyl benzoate $\rightarrow$ Benzaldehyde | $(d)$. $CH_3MgBr, H_2O$ |
Medium
View SolutionAcetone on addition to methyl magnesium bromide forms a complex,which on decomposition with acid gives $X$ and $Mg(OH)Br$. Which one of the following is $X$?
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