Give the definition of magnetic field and provide its unit.

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(A) The magnitude of the force $F$ on an electric charge $q$ moving with velocity $v$ in a magnetic field $B$ is given by the Lorentz force formula:
$F = B q v \sin \theta$
Rearranging for $B$:
$B = \frac{F}{q v \sin \theta}$
Definition: The magnitude of the magnetic field $B$ is defined as $1$ unit in the $SI$ system when a force of $1 \ N$ acts on a unit charge $(1 \ C)$ moving perpendicular to the magnetic field with a speed of $1 \ m/s$.
$SI$ unit derivation:
Unit of $B = \frac{\text{Unit of } F}{\text{Unit of } q \times \text{Unit of } v}$
$= \frac{1 \ N}{1 \ C \times 1 \ m/s} = 1 \ N \cdot C^{-1} \cdot s \cdot m^{-1}$
Since $1 \ C/s = 1 \ A$,the unit becomes:
$= 1 \ N \cdot A^{-1} \cdot m^{-1}$
This unit is also known as the Tesla $(T)$.

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In electromagnetic theory, electric and magnetic phenomena are related to each other. Therefore, the dimensions of electric and magnetic quantities must also be related. In the questions below, $[E]$ and $[B]$ stand for dimensions of electric and magnetic fields respectively, while $[\varepsilon_0]$ and $[\mu_0]$ stand for dimensions of the permittivity and permeability of free space respectively. $L$ and $T$ are dimensions of length and time respectively. All quantities are in $SI$ units.
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$(A)$ $[E]=[B][L][T]^{-1}$
$(B)$ $[E]=[B][L][T]$
$(C)$ $[E]=[B][L]^{-1}[T]$
$(D)$ $[E]=[B][L]^{-1}[T]^{-1}$
$(2)$ The relation between $[\varepsilon_0]$ and $[\mu_0]$ is:
$(A)$ $[\mu_0]=[\varepsilon_0][L]^2[T]^{-2}$
$(B)$ $[\mu_0]=[\varepsilon_0]^{-1}[L]^{-2}[T]^2$
$(C)$ $[\mu_0]=[\varepsilon_0][L]^{-2}[T]^2$
$(D)$ $[\mu_0]=[\varepsilon_0]^{-1}[L]^2[T]^{-2}$
Select the correct options for $(1)$ and $(2)$.

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